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9n^2+43n+24=0
a = 9; b = 43; c = +24;
Δ = b2-4ac
Δ = 432-4·9·24
Δ = 985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-\sqrt{985}}{2*9}=\frac{-43-\sqrt{985}}{18} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+\sqrt{985}}{2*9}=\frac{-43+\sqrt{985}}{18} $
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